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Here is the simplest construction method for the egg shaped rings of Woodhenge, which does not use a Pythagorean triangle of 17.5, 6, 18.5 Meg Yd sides, as employed by Thom, but the end result is one which could have influenced Thom into thinking that one had been used.
This construction brings into play the geometric methods descibed on previous pages.
The 120 ring is not marked on the ground, but must have a significance, perhaps because of the 120 MY perimeter of the Sarsen ring at Stonehenge just down the road. The difference between this radius of 17.647545... MY and the Pythagoras side of 17.5MY., is just 4.82 inches, the difference is even closer on the short side of 6MY, at plus 0.8 inches.
The sequence of construction would be :-
1. Draw a circle of 1 MY radius
2. The radius of the next circle is the vertical height of a 2 MY triangle drawn from the
2MY diameter circle.
3. Then mark out the interval between the rings, using a 10ft. triangle. (or the diameter
of a circle which has a perimeter of 10 MY.)
4. Now use the 5th ring as your base radius.
5. Draw an arc from this point, radius to the top of the 2MY diameter circle, to cut the
6. As can be seen from the above diagram, all other arcs can be drawn.
The intervals of 1 MY between Left and Right side radii are maintained.
Perimeters of Eggs increase by 20 MY
J.E.Wood, 'Sun, Moon and Standing Stones', p.45, states the average gap between the rings as being 2.64 metres, which is 8.6614.. ft. Vertical height of the Brown Triangle in the top most figure is 8.66025 ft.
The Major and Minor axis of the 160 MY perimeter, match up within inches to the published results of the Cunningtons.
(The diagram is based on Thom's work, but with additions.)
(My basic design without rounded out flat arcs).
Left hand fig. shows the relationship of a circumference of 2p to that of 2MY neatly encompassed by a hexagon.
Right hand fig. is those two circles with Thom's flattened arcs, which can also be drawn with reference to the diagram below.
Flat arcs rounded off. (Modified after Thom)
Note the 30°/60° triangle in the 'B' type circle.
ENGLISH, IRISH and ROMAN MILES
Another use of the 30°/60° triangle
I have recently come across some dimensions for this site after the
discovery of the concentric post holes.
1. Diameter of Stone Circle is given as 113 meters. This looks to me as though it could be 112.8096.. meters, or in my speak, 50 ´ MY². (Compare Woodhenge 20 x MY²)
2. Diameter of outer ring of Post holes is given as 95 meters. This is 311.679..ft. , radius 155.839.. ft., giving an SS of 89.97.. ft. A difference from 90 ft. of .31 inches. So my guess is that the circumference is 360 MY!. (SS 90 ´ 4 = 360).
Which is a diameter of 95.0272.. mtrs.
3. Diameter of inner ring of post holes is 23 meters. This equates to 27.735..MY, I think it is meant to be 10,000/360. (27.7777... MY). Why?
(Dimensions of the other rings were not given)