memmove()                Move a Block of Bytes
 
 #include   <string.h>
 #include   <mem.h>
 
 void       *memmove(destin,source,n);
 void       *destin;                     Destination
 void       *source;                     Source
 unsigned   n;                           Number of bytes
 
    memmove() copies a block of 'n' bytes from 'source' to 'destin'. If
    the source and destination blocks overlap, the copy direction is
    chosen so that overlapping bytes are copied correctly.
 
    Returns:    'destin' is returned.

Seealso:


 memcpy() 
 memset() 
 memcmp()