strchr()                 Find a Character in a String
 
 #include   <string.h>                   Required for declarations only
 
 char       *strchr(string,ch);
 char       *string;                     Source string
 int        ch;                          Character to be found
 
    strchr() finds the occurrence of 'ch' in 'string.  The terminating
    null character ('\0') is included in the search.  strchr() is case
    sensitive.
 
    Returns:    A pointer to the character, if found, or NULL if it's not
                found.
 
      Notes:    strchr() expects to operate on null-terminated strings.
                No overflow checking is done when strings are copied or
                appended.
 
  -------------------------------- Example ---------------------------------
 
    This example searches for a lowercase 'a' in 'str'.
 
          #include <string.h>
          #include <stdio.h>            /* for printf */
 
          char str[50] = "All in a good day's work.";
          int ch = 'a';
          char *rslt;
 
          main()
          {
                if ((rslt = strchr(str,ch)) != NULL)
                   printf("character found: %c  \n",*rslt);
                else
                   printf("character not found.");
          }

Seealso:


 strrchr() 
 strpbrk()