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Megalithic Foot and Megalithic Inch
From the Cup and Ring marks found on stones and measured by Thom, a
Megalithic Inch was determined to be one fortieth (1/40) of a Megalithic Yard, or
.8169inches if Thom's MY is taken as 2.723.
When a 45° triangle is drawn with sides of 1,1,Ö2, and the Ö2 side is then used as the radius of a circle, it will be found that the short side (SS) of the 30°/ 60° triangle which has been demonstrated earlier, will be .81649 units. (see diagram below, and note also that inverse tan .81649 is 39.2315+ degrees, see angle of ellipse on previous page).
Forty of these units (calling them Inches), would then be 2.721633 feet, a difference of just .007" from a MY of 2.720699. (where1/40 th would be .816209 inches).
I don't think the Stone Age builders were working to 1/1000 th of an inch, so .816" or .817" would be acceptable at this small scale.
HOWEVER!
Put 1 inch as the Short Side of the 30/60 triangle, and the resulting circumference will be 10.882+ inches, 1/3 of a Meg Yard. I call it a Megalithic Foot.
Thus the number of Inches in an SS will be the number of Meg Feet in the Circumference.
198 Meg.ft. circumference = 198" SS, or 1Rod, Pole or Perch. And the obvious length for a Meg. Inch is 10.882+ / 12 = .90689+ inches.
I am a Megalithic Man. My thumb at the base of the nail is 1 inch. My bare foot is 10.88 inches heel to toe. (I take a size 10 shoe). From my crotch to floor (standing in bare feet), I am exactly 2.72 ft.
Those who insist that a Megalithic Yard is equivalent to a man's pace do actually have a point. Our present foot of 12 inches is much too long for the length of an average person's bare foot.